Wishbone to LPC (Low-Pin Count) Bridge, includes master and slave modules. Supports 8-bit I/O Read and Write cycles, 8-bit Memory Read/Write cycles, DMA cycles, and up to 32-bit Firmware memory read/write cycles. Serial IRQ support is also provided. None of this has been tested (yet) with a third-party LPC Peripheral or Host.
标签： Wishbone Supports includes Low-Pin
上传时间： 2014-12-20
上传用户：古谷仁美
ds18b20 digitsl 1-wire thermometer with programmable resolution code for initialization write and read and convert temperature functions
标签： initialization programmable thermometer resolution
上传时间： 2017-08-29
上传用户：225588
All inputs of the C16x family have Schmitt-Trigger input characteristics. These Schmitt-Triggers are intended to always provide proper internal low and high levels, even if anundefined voltage level (between TTL-VIL and TTL-VIH) is externally applied to the pin.The hysteresis of these inputs, however, is very small, and can not be properly used in anapplication to suppress signal noise, and to shape slow rising/falling input transitions.Thus, it must be taken care that rising/falling input signals pass the undefined area of theTTL-specification between VIL and VIH with a sufficient rise/fall time, as generally usualand specified for TTL components (e.g. 74LS series: gates 1V/us, clock inputs 20V/us).The effect of the implemented Schmitt-Trigger is that even if the input signal remains inthe undefined area, well defined low/high levels are generated internally. Note that allinput signals are evaluated at specific sample points (depending on the input and theperipheral function connected to it), at that signal transitions are detected if twoconsecutive samples show different levels. Thus, only the current level of an input signalat these sample points is relevant, that means, the necessary rise/fall times of the inputsignal is only dependant on the sample rate, that is the distance in time between twoconsecutive evaluation time points. If an input signal, for instance, is sampled throughsoftware every 10us, it is irrelevant, which input level would be seen between thesamples. Thus, it would be allowable for the signal to take 10us to pass through theundefined area. Due to the sample rate of 10us, it is assured that only one sample canoccur while the signal is within the undefined area, and no incorrect transition will bedetected. For inputs which are connected to a peripheral function, e.g. capture inputs, thesample rate is determined by the clock cycle of the peripheral unit. In the case of theCAPCOM unit this means a sample rate of 400ns @ 20MHz CPU clock. This requiresinput signals to pass through the undefined area within these 400ns in order to avoidmultiple capture events.For input signals, which do not provide the required rise/fall times, external circuitry mustbe used to shape the signal transitions.In the attached diagram, the effect of the sample rate is shown. The numbers 1 to 5 in thediagram represent possible sample points. Waveform a) shows the result if the inputsignal transition time through the undefined TTL-level area is less than the time distancebetween the sample points (sampling at 1, 2, 3, and 4). Waveform b) can be the result ifthe sampling is performed more than once within the undefined area (sampling at 1, 2, 5,3, and 4).Sample points:1. Evaluation of the signal clearly results in a low level2. Either a low or a high level can be sampled here. If low is sampled, no transition willbe detected. If the sample results in a high level, a transition is detected, and anappropriate action (e.g. capture) might take place.3. Evaluation here clearly results in a high level. If the previous sample 2) had alreadydetected a high, there is no change. If the previous sample 2) showed a low, atransition from low to high is detected now.
上传时间： 2013-10-23
上传用户：copu
ARM下 Implement matrix multiplication of 2 square matrices, with data read from an input file and printed both to the console and to an output file. • Assume a file with correct data (no garbage, characters, etc.). • you must check and provide appropriate execution for 2 extra cases, namely when the matrix size given is either “0” , or when the size is greater than the maximum handled of “5” . In these 2 cases you must implement the following behaviour: o If size = 0, then print a message “Size = 0 is unacceptable” and continue by reading the next size for the next 2 matrices (if not end of file). o If size >5, then print two messages: “Size is too big - unacceptable”. Then read and discard the next (size2 ) integers and continue by reading the next size for the next 2 matrices (if not end of file).
标签： multiplication Implement matrices matrix
上传时间： 2014-08-30
上传用户：dsgkjgkjg
* 高斯列主元素消去法求解矩阵方程AX=B,其中A是N*N的矩阵,B是N*M矩阵 * 输入: n----方阵A的行数 * a----矩阵A * m----矩阵B的列数 * b----矩阵B * 输出: det----矩阵A的行列式值 * a----A消元后的上三角矩阵 * b----矩阵方程的解X
上传时间： 2015-07-26
上传用户：xauthu
Delphi and C++ Builder component for direct access to IO ports on Windows 95, Windows 98 and Windows NT/2000. Provides properties for reading and writing bytes, words and doublewords from/to IO ports. New fast block data transfer methods enable to read and write megabytes of data per second.
标签： Windows and component Builder
上传时间： 2015-10-25
上传用户：bjgaofei
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
标签： represented integers group items
上传时间： 2016-01-17
上传用户：jeffery
NAME Control_AT24Cxx This collection of routines allows an AT89C2051 microcontroller to read and write the AT24Cxx family of serial CMOS EEPROMS. This version of the code is compatible only with the AT89C2051 due to the location of the data buffer and stack in RAM. The code may be modified to work with the AT89C1051 by relocating or resizing the buffer and stack to fit into the smaller amount of RAM available in the AT89C1051. Note that the minimum size of the buffer is determined by the page size of the AT24Cxx.
标签： microcontroller Control_AT collection routines
上传时间： 2013-12-13
上传用户：asddsd
(1) 、用下述两条具体规则和规则形式实现.设大写字母表示魔王语言的词汇 小写字母表示人的语言词汇 希腊字母表示可以用大写字母或小写字母代换的变量.魔王语言可含人的词汇. (2) 、B→tAdA A→sae (3) 、将魔王语言B(ehnxgz)B解释成人的语言.每个字母对应下列的语言.
上传时间： 2013-12-30
上传用户：ayfeixiao
1.有三根杆子A,B,C。A杆上有若干碟子 2.每次移动一块碟子,小的只能叠在大的上面 3.把所有碟子从A杆全部移到C杆上 经过研究发现，汉诺塔的破解很简单，就是按照移动规则向一个方向移动金片： 如3阶汉诺塔的移动：A→C,A→B,C→B,A→C,B→A,B→C,A→C 此外，汉诺塔问题也是程序设计中的经典递归问题
上传时间： 2016-07-25
上传用户：gxrui1991
