This paper examines the asymptotic (large sample) performance of a family of non-data aided feedforward (NDA FF) nonlinear least-squares (NLS) type carrier frequency estimators for burst-mode phase shift keying (PSK) modulations transmitted through AWGN and flat Ricean-fading channels. The asymptotic performance of these estimators is established in closed-form expression and compared with the modified Cram`er-Rao bound (MCRB). A best linear unbiased estimator (BLUE), which exhibits the lowest asymptotic variance within the family of NDA FF NLS-type estimators, is also proposed.
标签： performance asymptotic examines non-data
上传时间： 2015-12-30
上传用户：225588
计算机彩色显示器显示色彩的原理与彩色电视机一样，都是采用R（Red）、G（Green）、B（Blue）相加混色的原理：
上传时间： 2016-02-12
上传用户：zhouchang199
embedded expert system engine for xps这个项目提供一个“嵌入式专家系统”，如，一个有限能力的推理机，带有一套从 X-ray光电子光谱学的演示规则。
标签： embedded expert engine system
上传时间： 2016-02-23
上传用户：refent
PNG开放源接口 The interface has been designed to be as simple and intuitive as possible. It supports plotting and reading in the RGB (red, green, blue), HSV (hue, saturation, value/brightness) and CMYK (cyan, magenta, yellow, black) colour spaces, basic shapes, scaling, bilinear interpolation, full TrueType antialiased and rotated text support, bezier curves, opening existing PNG images and more.
标签： interface intuitive designed possible
上传时间： 2013-12-23
上传用户：qilin
爱因斯坦在20世纪初出的IQ测试题 题目 在一条街上，有5座房子，喷了五种颜色，每个房子里住着不同国籍的人，每个人喝不同的饮料，抽不同品牌 的香烟，养不同的宠物。 提示 1、英国人住红色房子 2、瑞典人养狗 3、丹麦人喝茶 4、绿色房子在白色房子左面 5、绿色房子主人喝咖啡 6、抽Pall Mall香烟的人养鸟 7、黄色房子主人抽Dunhill香烟 8、住在中间房子的人喝牛奶 9、挪威人住第一间房 10、抽Blends香烟的人住在养猫的人隔壁 11、养马的人住抽Dunhill香烟的人隔壁 12、抽Blue Master的人喝啤酒 13、德国人抽Prince香烟 14、挪威人住蓝色房子隔壁 15、抽Blends香烟的人有一个喝水的邻居 问题是：谁养鱼？问题补充：他说世界上有98％的人答不出来,你是那2％里面的吗？ 的程序实现方法
上传时间： 2014-01-09
上传用户：王庆才
PlotSphereIntensity(azimuth, elevation) PlotSphereIntensity(azimuth, elevation, intensity) h = PlotSphereIntensity(...) Plots the intensity (as color) of a number of points on a unit sphere. Input: azimuth (phi), in degrees elevation (theta), in degrees intensity (optional, if not provided, a green sphere is produced) All inputs must be vectors or matrices of the same size. Data does not have to be evenly spaced. When there aren t enough points to draw a smooth sphere, additional points (with color) are interpolated. Output: h - a handle to the patch object The axes are also plotted: positive x axis is red positive y axis is green positive z axis is blue
标签： PlotSphereIntensity elevation azimuth intensity
上传时间： 2014-01-15
上传用户：ruan2570406
看n2实例 #Create a simulator object set ns [new Simulator] #Define different colors for data flows #$ns color 1 Blue #$ns color 2 Red #Open the nam trace file set nf [open out-1.nam w] $ns namtrace-all $nf set f0 [open out0.tr w] set f1 [open out1.tr w] #Define a finish procedure proc finish {} { global ns nf $ns flush-trace #Close the trace file close $nf #Execute nam on the trace file exit 0 } #Create four nodes set n0 [$ns node] set n1 [$ns node] set n2 [$ns node] set n3 [$ns node] #Create links between the nodes $ns duplex-link $n0 $n2 1Mb 10ms
标签： simulator Simulator different Create
上传时间： 2016-07-02
上传用户：wfl_yy
bluetooth 驱动，支持各家blue芯片，比如CSR BC02
上传时间： 2014-09-05
上传用户：xhz1993
This a GUI based system. The GUI is invoked from the command line by typing "ui_start". The GUI is self explanatory. Tool tips are given in blue color. The cursor needs to be positioned on these for detailed explanation. The main file is "runsim.m". In these simulations the SISO option is not explicitly given. This is because the SISO result for a particular type of modulation is shown in every plot for purposes of comparison. This software has been tested on MATLAB version 6.0 and above with signal processing and communication toolbox options.
上传时间： 2016-08-24
上传用户：杜莹12345
51单片连tcs230的源程序，绝对原创，可以记忆颜色。 #define uchar unsigned char #include <reg52.h> #include<math.h> sbit S0=P1^7 sbit S1=P1^0 //端口定义 sbit S2=P1^1 sbit S3=P1^2 sbit OE=P1^3 sbit OUT=P3^4 //频率从TO口输入 sbit key0=P1^5 sbit LED=P1^6 sbit a=P3^0 sbit b=P3^1 uchar color //1:blue 2:green 3:red uchar T[4] //color timer uchar TH[4] uchar TL[4] uchar bizhi[4] void time1() interrupt 3 { TH[color]=TH0 TL[color]=TL0 T[color]=(TH[color]*0xff+TL[color]) TR0=0 //关定时器 TR1=0 TH1=0xB1 TL1=0xE0 //归0 TH0=0x00 TL0=0x00 //归0 }
上传时间： 2016-11-26
上传用户：秦莞尔w
