选择文件 X 双色球彩票过滤器 绿色免费版
上传时间： 2020-11-27
上传用户：
选择文件 X 双色球彩票管理系统(LotterySystem)
标签： LotterySystem 双色 管理系统
上传时间： 2020-11-27
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SI-PNP 60 V 0,6 A 0,6 W 100 MHz
标签： 2N2905
上传时间： 2021-07-02
上传用户：xiangshuai
This paper presents a new type of electromagnetic damper with rotating inertial mass that has been devel oped to control the vibrations of structures subjected to earthquakes. The electromagnetic inertial mass damper (EIMD) consists of a ball screw that converts axial oscillation of the rod end into rotational motion of the internal flflywheel and an electric generator that is turned by the rotation of the inner rod. The EIMD is able to generate a large inertial force created by the rotating flflywheel and a variable damping force devel oped by the electric generator. Device performance tests of reduced-scale and full-scale EIMDs were under taken to verify the basic characteristics of the damper and the validity of the derived theoretical formulae. Shaking table tests of a three-story structure with EIMDs and earthquake response analyses of a building with EIMDs were conducted to demonstrate the seismic response control performance of the EIMD. The EIMD is able to reduce story drifts as well as accelerations and surpasses conventional types of dampers in reducing acceleration responses.
标签： electromagnetic response Seismic control using
上传时间： 2021-11-04
上传用户：a1293065
This book addresses programmer attitudes, but it’s not some kind of psychology textbook. We’ll investigate many topics, including: Source code presentation Defensive coding techniques How to debug programs effectively Good teamworking skills Managing your source code Take a quick glance through the table of contents to see exactly what’s covered. What is the rationale behind my selection of topics? I’ve been mentor- ing trainee programmers for many years, and these are the topics that have come up time and time again. I’ve also worked in the software factory for long enough to have seen the recurring problems—I address these too. If you can conquer all of these programming demons, you’ll progress from an apprentice coder to a real code craftsman.
标签： excellent practice writing Craft Code code the of
上传时间： 2021-11-09
上传用户：danix800
include<reg52.h> #define uint unsigned int #define uchar unsigned char uint temp,aa,wang,qian,bai,shi,ge; sbit dula=P2^6; sbit wela=P2^7; uchar code table[]={ 0x3f,0x06,0x5b,0x4f, 0x66,0x6d,0x7d,0x07, 0x7f,0x6f,0x77,0x7c, 0x39,0x5e,0x79,0x71}; void display( uint wang,uint qian,uint bai,uint shi,uint ge); void delay(uint z); void init(); void main() { init();//初始化子程序 while(1) { if(aa==20) { aa=0; temp++; if(temp==99999) { temp=0; } wang=temp/10000; qian=(temp-wang*10000)/1000; bai=(temp-wang*10000-qian*1000)/100; shi=(temp-wang*10000-qian*1000-bai*100)/10; ge=temp%10; } display(wang,qian, bai,shi,ge); } } void delay(uint z) { uint x,y; for(x=z;x>0;x--) for(y=110;y>0;y--); } void display(uint wang,uint qian,uint bai,uint shi,uint ge) { dula=1; P0=table[wang]; dula=0; P0=0xff; wela=1; P0=0xfe; wela=0; delay(1); dula=1; P0=table[qian]; dula=0; P0=0xff; wela=1; P0=0xfd; wela=0; delay(1); dula=1; P0=table[bai]; dula=0; P0=0xff; wela=1; P0=0xfb; wela=0; delay(1); dula=1; P0=table[shi]; dula=0; P0=0xff; wela=1; P0=0xf7; wela=0; delay(1); dula=1; P0=table[ge]; dula=0; P0=0xff; wela=1; P0=0xef; wela=0; delay(1); } void init() { wela=0; dula=0; temp=0; TMOD=0x01; TH0=(65536-50000)/256; TL0=(65536-50000)%256; EA=1; ET0=1; TR0=1; } void timer0() interrupt 1 { TH0=(65536-50000)/256; TL0=(65536-50000)%256; aa++; } include<reg52.h> #define uint unsigned int #define uchar unsigned char uint temp,aa,wang,qian,bai,shi,ge; sbit dula=P2^6; sbit wela=P2^7; uchar code table[]={ 0x3f,0x06,0x5b,0x4f, 0x66,0x6d,0x7d,0x07, 0x7f,0x6f,0x77,0x7c, 0x39,0x5e,0x79,0x71}; void display( uint wang,uint qian,uint bai,uint shi,uint ge); void delay(uint z); void init(); void main() { init();//初始化子程序 while(1) { if(aa==20) { aa=0; temp++; if(temp==99999) { temp=0; } wang=temp/10000; qian=(temp-wang*10000)/1000; bai=(temp-wang*10000-qian*1000)/100; shi=(temp-wang*10000-qian*1000-bai*100)/10; ge=temp%10; } display(wang,qian, bai,shi,ge); } } void delay(uint z) { uint x,y; for(x=z;x>0;x--) for(y=110;y>0;y--); } void display(uint wang,uint qian,uint bai,uint shi,uint ge) { dula=1; P0=table[wang]; dula=0; P0=0xff; wela=1; P0=0xfe; wela=0; delay(1); dula=1; P0=table[qian]; dula=0; P0=0xff; wela=1; P0=0xfd; wela=0; delay(1); dula=1; P0=table[bai]; dula=0; P0=0xff; wela=1; P0=0xfb; wela=0; delay(1); dula=1; P0=table[shi]; dula=0; P0=0xff; wela=1; P0=0xf7; wela=0; delay(1); dula=1; P0=table[ge]; dula=0; P0=0xff; wela=1; P0=0xef; wela=0; delay(1); } void init() { wela=0; dula=0; temp=0; TMOD=0x01; TH0=(65536-50000)/256; TL0=(65536-50000)%256; EA=1; ET0=1; TR0=1; } void timer0() interrupt 1 { TH0=(65536-50000)/256; TL0=(65536-50000)%256; aa++; } include<reg52.h> #define uint unsigned int #define uchar unsigned char uint temp,aa,wang,qian,bai,shi,ge; sbit dula=P2^6; sbit wela=P2^7; uchar code table[]={ 0x3f,0x06,0x5b,0x4f, 0x66,0x6d,0x7d,0x07, 0x7f,0x6f,0x77,0x7c, 0x39,0x5e,0x79,0x71}; void display( uint wang,uint qian,uint bai,uint shi,uint ge); void delay(uint z); void init(); void main() { init();//初始化子程序 while(1) { if(aa==20) { aa=0; temp++; if(temp==99999) { temp=0; } wang=temp/10000; qian=(temp-wang*10000)/1000; bai=(temp-wang*10000-qian*1000)/100; shi=(temp-wang*10000-qian*1000-bai*100)/10; ge=temp%10; } display(wang,qian, bai,shi,ge); } } void delay(uint z) { uint x,y; for(x=z;x>0;x--) for(y=110;y>0;y--); } void display(uint wang,uint qian,uint bai,uint shi,uint ge) { dula=1; P0=table[wang]; dula=0; P0=0xff; wela=1; P0=0xfe; wela=0; delay(1); dula=1; P0=table[qian]; dula=0; P0=0xff; wela=1; P0=0xfd; wela=0; delay(1); dula=1; P0=table[bai]; dula=0; P0=0xff; wela=1; P0=0xfb; wela=0; delay(1); dula=1; P0=table[shi]; dula=0; P0=0xff; wela=1; P0=0xf7; wela=0; delay(1); dula=1; P0=table[ge]; dula=0; P0=0xff; wela=1; P0=0xef; wela=0; delay(1); } void init() { wela=0; dula=0; temp=0; TMOD=0x01; TH0=(65536-50000)/256; TL0=(65536-50000)%256; EA=1; ET0=1; TR0=1; } void timer0() interrupt 1 { TH0=(65536-50000)/256; TL0=(65536-50000)%256; aa++; }
标签： 矩阵式键盘
上传时间： 2021-12-18
上传用户：2590813506
1. Scope ......................................................................................................................................................................... 12. DDR4 SDRAM Package Pinout and Addressing ....................................................................................................... 22.1 DDR4 SDRAM Row for X4,X8 and X16 ................................................................................................................22.2 DDR4 SDRAM Ball Pitch........................................................................................................................................22.3 DDR4 SDRAM Columns for X4,X8 and X16 ..........................................................................................................22.4 DDR4 SDRAM X4/8 Ballout using MO-207......................................................................................................... 22.5 DDR4 SDRAM X16 Ballout using MO-207.............................................................................................................32.6 Pinout Description ..................................................................................................................................................52.7 DDR4 SDRAM Addressing.....................................................................................................................................73. Functional Description ...............................................................................................................................................83.1 Simplified State Diagram ....................................................................................................................................83.2 Basic Functionality..................................................................................................................................................93.3 RESET and Initialization Procedure .....................................................................................................................103.3.1 Power-up Initialization Sequence .............................................................................................................103.3.2 Reset Initialization with Stable Power ......................................................................................................113.4 Register Definition ................................................................................................................................................123.4.1 Programming the mode registers .............................................................................................................123.5 Mode Register ......................................................................................................................................................134. DDR4 SDRAM Command Description and Operation ............................................................................................. 244.1 Command Truth Table ..........................................................................................................................................244.2 CKE Truth Table ...................................................................................................................................................254.3 Burst Length, Type and Order ..............................................................................................................................264.3.1 BL8 Burst order with CRC Enabled .........................................................................................................264.4 DLL-off Mode & DLL on/off Switching procedure ................................................................................................274.4.1 DLL on/off switching procedure ...............................................................................................................274.4.2 DLL “on” to DLL “off” Procedure ..............................................................................................................274.4.3 DLL “off” to DLL “on” Procedure ..............................................................................................................284.5 DLL-off Mode........................................................................................................................................................294.6 Input Clock Frequency Change ............................................................................................................................304.7 Write Leveling.......................................................................................................................................................314.7.1 DRAM setting for write leveling & DRAM termination function in that mode ............................................324.7.2 Procedure Description .............................................................................................................................334.7.3 Write Leveling Mode Exit .........................................................................................................................34
标签： DDR4
上传时间： 2022-01-09
上传用户：
结构体的具体尺寸如下所示：a=1.20h=0.620其中介质锥的介电常数E=2.0。选定工作频率为f=15GHz相对应的真空中的波长为0=20mm，这样结构体的儿何尺寸己经完全确定，下面介绍求解的全过程选定求解方式为（Solution Type）Driven modal1.建立所求结构体的几何模型（单位：mm）。由于此结构体的几何形状较简单，使用工具栏中的Draw命令可直接画出，这里不再赘述述。画出的结构体如图4.1.2所示。2.充结构体的材料选定结构体中的锥体部分，添加其介电常数Er=20的介质材料注：如果HSS中没有提供与所需参数完全相同的材料，用户可以通过新建材料或修改已有材料，使其参数满足用户需求设定结构体的边界条件及其激励源a.选定结构体的贴片部分，设定其为理想导体（PerE）。b.画出尺寸为X×Y×Z=70mm×70mm×40mm的长方体作为辐射边界，并设定其边界条件为辐射边界条件（Radiation Boundary）。c.由于要求出结构体的RCS，因此设定激励源为平面入射波（Incident Wave Source）。如图4.1.3所示。4.设定求解细节，检验并求解a.设定求解过程的工作频率为f=15GHz.其余细节设定如图4.1.4所示。b.设定远区辐射场的求解（Far Field Radiation Sphere栏的设定）。c.使用 Validation check命令进行检验，无错误发生，下一步运行命令 Analyze，对柱锥结构体进行求解。如图4.1.5和4.1.6所示。
上传时间： 2022-03-10
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以STC12C5A60S2单片机为控制核心,采用2.4G(JF24D)无线遥控模块进行无线发射与接收,设计了一种双电机遥控船模控制系统.该系统通过切换档杆实现前进后退,方向盘左右转动、暂停按钮等控制直流电机的正转、反转、暂停,使得电机驱动的遥控船模实现前进后退、左右转向、暂停等功能,有效解决了驱动功率小和船模之间相互干扰等问题,可广泛应用于遥控船模领域.Using STC12C5A60S2 single-chip microcomputer as the controller and 2.4 G(JF24D)wireless remote control module for wireless transmission and reception, a dual-motor remote control ship model control system is designed. The system realizes forward and backward by switching the gear lever. The steering wheel rotates left and right and the pause button controls the forward, reverse and pause of the dc motor. The remote controller of ship model driven by the motor realizes forward and backward, left and right steering, pause and other functions. The ship model control system can effectively solve the problems of small driving power and mutual interference between ship models, and can be widely used in the field of remote controller of ship model.
上传时间： 2022-03-27
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LED 线阵显示装置, 分为 LED 线性旋转显示主机和图文录入器两部分。主机用直流电机带动由红绿 LED 组成的线阵旋转, 同时线阵按照时序依次切换显示状态, 在固定区域利用视觉暂留效果形成 16×16 点阵, 用以显示图文;图文录入器用 HMI 触控屏作为人机交互界面, 实现图文录入和回放功能。主机与图文录入器通过无线通信方式进行信息交互,可由图文录入器控制主机切换不同工作任务, 以及改变线阵显示内容。The LED linear array display device is divided into two parts:the one is the main unit used to display content,and the other one is used to input the contents.The main unit is driven by a DC motor to rotate the linear array composed by red and green light emitting diodes.At the same time,the 16×16 dot matrix that switching the display state according to the time sequence on the main unit displays pictures and texts in the fixed area,by using the visual temporary effect.The HMI touch screen is used as human machine interface to realize the function that input and playback pictures and texts.The two parts of the device communicate with each other through wireless communication.The image and text input controller can control the main unit to switch different tasks and change the content of linear array displayed.
标签： stc12c5a60s2 单片机 led
上传时间： 2022-03-28
上传用户：jiabin
