该源码为C8051F120混合片上数据采集系统中实现4~32768点数据的FFT运算功能。所占的代码空间小，运行快。
上传时间： 2013-12-18
上传用户：zhouli
可实现简单的加法运算功能 范围-32768~~~32767
上传时间： 2017-01-18
上传用户：13160677563
基于AT89S52单片机的nRF2401无线模块开发板 资料齐全
上传时间： 2014-06-14
上传用户：nshark
多数程序设计语言处理整数的能力时有限的，如C语言中，int类型数据范围是-32768－32767。实际问题的处理过程中往往涉及大整数的运算，如RSA加密算法要求至少64bit的整数，设计算法实现大整数的加减运算。
上传时间： 2014-07-08
上传用户：偷心的海盗
IO 驱动 LCD , *** *** *** *** *** *** *** *** FILE NAME: IO_LCD MCU: HT46R22 MASK OPTION: WAKE-UP: PA6,PA7 PULL-HIGH: PA,PB,PC IIC: DISABLE PFD: DISABLE PWM: DISABLE WDT: ENABLE CLRWDT: ONE WDT CLOCK SOURCE: T1 WDT TIME OUT SELECT: WDT CLOCK SOURCE/32768 LVR: DISABLE OSC: CRYSTAL SYSVOLT: 3.0V SYSFRAG: 4000KHZ AUTHOR: RADOME HISTORY: 2005.08.
上传时间： 2014-12-21
上传用户：watch100
计算xk+1除CRC-CCITT后的余式，k从1到32768
上传时间： 2014-01-19
上传用户：ruixue198909
计算xk+1除CRC-CCITT后的余式，k从1到32768
上传时间： 2016-06-18
上传用户：ynsnjs
计算xk+1除CRC-32后的余式，k从1到32768
上传时间： 2013-11-25
上传用户：wangchong
atmega8控制的4位时钟，32768时钟源
上传时间： 2013-12-17
上传用户：exxxds
For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
标签： Limit following solving problem
上传时间： 2014-01-12
上传用户：362279997
