无论是高压系统还是低压系统，电力系统中性点采用电阻接地的方式越来越普遍。奥兰电气中性点电阻可以限制接地过电压和过电流限制在安全范围内、提高继电保护灵敏度，同时自身造价相对较低，运行持久安全，安装灵活方便。中性点接地电阻柜可将零散的单相变压器、电阻器、隔离开关、电流互感器、温控器、计数器、接地监控（记录）装置、接地故障查找装置.接地保护输出端子等电器设备整体组合在一个封闭金属柜内成套供货；配备电流互感器和动作记录仪，正常时可监视中性点不平衡电流，出现单相接地故障时，可记录动作次数，且可为保护和监控系统提供模拟量输出；装设单相隔离开关，以便在进行检修或实验时隔离电源。接地故障查找装置可以迅速查找到接地故障点以便人工排除接地故障。如果系统变压器采用三角形接线，本产品则加三相接地变压器与之配合使用，对抑制系统过电压、防止各种冲击有很好的作用
上传时间： 2013-11-05
上传用户：ainimao
C++完美演绎 经典算法 如 /* 头文件：my_Include.h */ #include <stdio.h> /* 展开C语言的内建函数指令 */ #define PI 3.1415926 /* 宏常量，在稍后章节再详解 */ #define circle(radius) (PI*radius*radius) /* 宏函数，圆的面积 */ /* 将比较数值大小的函数写在自编include文件内 */ int show_big_or_small (int a,int b,int c) { int tmp if (a>b) { tmp = a a = b b = tmp } if (b>c) { tmp = b b = c c = tmp } if (a>b) { tmp = a a = b b = tmp } printf("由小至大排序之后的结果:%d %d %d\n", a, b, c) } 程序执行结果： 由小至大排序之后的结果:1 2 3 可将内建函数的include文件展开在自编的include文件中 圆圈的面积是=201.0619264
标签： my_Include include define 3.141
上传时间： 2014-01-17
上传用户：epson850
Kismet is an 802.11b network sniffer and network dissector. It is capable of sniffing using most wireless cards, automatic network IP block detection via UDP, ARP, and DHCP packets, Cisco equipment lists via Cisco Discovery Protocol, weak cryptographic packet logging, and Ethereal and tcpdump compatible packet dump files. It also includes the ability to plot detected networks and estimated network ranges on downloaded maps or user supplied image files. Kismet是一个针对IEEE802.11b无线局域网的嗅探和包分析器，支持大多数无线网卡，支持自动检测UDP、ARP和DHCP的数据包，支持通过CDP协议检测思科网络设备，支持加密数据包记录，采用与Ethereal和Tcpdump兼容的的数据包记录文件，支持通过用户提供地图来检测和评估无线网络范围。
标签： network dissector sniffing capable
上传时间： 2014-11-26
上传用户：wweqas
数字运算，判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no
上传时间： 2015-05-21
上传用户：daguda
源代码\用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a，b，c依次序排列时，有13种不同的序列关系： a=b=c,a=b<c,a<b=v,a<b<c,a<c<b a=c<b,b<a=c,b<a<c,b<c<a,b=c<a c<a=b,c<a<b,c<b<a 若要将n个数依序列，设计一个动态规划算法，计算出有多少种不同的序列关系， 要求算法只占用O(n),只耗时O(n*n).
上传时间： 2013-12-26
上传用户：siguazgb
数据库存储过程，从输入data_object型参数DataObject中取出数据组成记录插入ORACLE数据库的表PRC_PAGO中，如果主键重复则更新改记录部分内容。
上传时间： 2015-12-30
上传用户：thesk123
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
标签： represented integers group items
上传时间： 2016-01-17
上传用户：jeffery
8255A控制步进电机汇编程序 步进电机作为执行器件，广泛用于自动控制系统、印字位置的控制及XY记录仪的无关控制等各个领域，而步进电机最适宜于用微处理器来控制，此法应用于实验教学、科研中效果良好。 1、实现全数字化驱动电路 设计思路是采用步进脉冲分配器专用芯片PMM8713和程序计数器8253的方法。图1是采用可编程计数器8253、8255和PMM8713芯片的全数字控制方式接线图。在单片机系统中，只连接8253、8255和PMM8713各一个。
上传时间： 2016-03-16
上传用户：cmc_68289287
用游标的方法实现对称差的计算，即 （A-B）+（B-A）
上传时间： 2016-05-23
上传用户：远远ssad
词法分析器 对输入一个函数，并对其分析main() { int a,b a = 10 b = a + 20 }
上传时间： 2013-12-20
上传用户：hfmm633
