词法分析器：源程序的运行方式： 运行程序 输入一个已存在的文本文档的文件名。如：input.txt 如果要对整个程序进行语法分析，则按‘y’键，否则按‘n’键 如果要对程序进行语法分析，则按‘y’键，否则按‘n’键 程序结束
上传时间： 2014-01-22
上传用户：zhaiyanzhong
对c语言的简单语法分析器 文件说明： input.txt内为输入的源程序，包括for，while和if else控制等 output.txt内为输出的二元单词序列 k.txt为关键字表 l.txt为运算符和界符表 i.txt为该输入的源程序的标志符 c.txt为常数表 个别表需要序列号，这时各表的序列号默认为从1开始，每行加1。 使用说明： 在提示符下输入input.txt文件的路径和文件名字， 运行完成后，打开文件output.txt看结果。
上传时间： 2013-12-23
上传用户：pompey
Sga.c 基本遗传算法源程序, 输入数据文件input，
上传时间： 2015-04-27
上传用户：youth25
The Art of Assembly Language Amazing! You’re actually reading this. That puts you into one of three categories: a student who is being forced to read this stuff for a class, someone who picked up this book by accident (probably because you have yet to be indoctrinated by the world at large), or one of the few who actually have an interest in learning assembly language.
标签： Assembly Language actually Amazing
上传时间： 2015-04-30
上传用户：asddsd
Turbo Pascal Field Input Routines.
标签： Routines Pascal Turbo Field
上传时间： 2015-05-05
上传用户：miaochun888
ARM下 Implement matrix multiplication of 2 square matrices, with data read from an input file and printed both to the console and to an output file. • Assume a file with correct data (no garbage, characters, etc.). • you must check and provide appropriate execution for 2 extra cases, namely when the matrix size given is either “0” , or when the size is greater than the maximum handled of “5” . In these 2 cases you must implement the following behaviour: o If size = 0, then print a message “Size = 0 is unacceptable” and continue by reading the next size for the next 2 matrices (if not end of file). o If size >5, then print two messages: “Size is too big - unacceptable”. Then read and discard the next (size2 ) integers and continue by reading the next size for the next 2 matrices (if not end of file).
标签： multiplication Implement matrices matrix
上传时间： 2014-08-30
上传用户：dsgkjgkjg
This zip describes how two SSCs in I2S mode play and record wave files through a two-input data method. Includes main.html file for help.
标签： describes two-input through record
上传时间： 2013-12-23
上传用户：lhw888
2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1. Input One positive integer on each line, the value of n. Output If the minimum x exists, print a line with 2^x mod n = 1. Print 2^? mod n = 1 otherwise. You should replace x and n with specific numbers. Sample Input 2 5 Sample Output 2^? mod 2 = 1 2^4 mod 5 = 1
标签： mod satisfies minimum number
上传时间： 2015-06-02
上传用户：qlpqlq
* * Input * bin_data : binary data * bin_size : binary data length * Mode : operation mode * BASE64_NeedCRLF ---- Need a CRLF every 64 base64-character * BASE64_NotCRLF ---- Need not CRLF between 64 base64-character * * Output * char data * char data length * * Return * 0: success -1: error
标签： binary data operation bin_data
上传时间： 2015-06-04
上传用户：ZJX5201314
Routine mampres: To obtain amplitude response from h(exp(jw)). input parameters: h :n dimensioned complex array. the frequency response is stored in h(0) to h(n-1). n :the dimension of h and amp. fs :sampling frequency (Hz). iamp:If iamp=0: The Amplitude Res. amp(k)=abs(h(k)) If iamp=1: The Amplitude Res. amp(k)=20.*alog10(abs(h(k))). output parameters: amp :n dimensioned real array. the amplitude-frequency response is stored in amp(0) to amp(n-1). Note: this program will generate a data file "filename.dat" . in chapter 2
标签： dimensione parameters amplitude response
上传时间： 2013-12-19
上传用户：xfbs821
