武林DLL注入源码 VB调用 Private Declare Function CallHotKey Lib "wulin.dll" (ByVal hWnd As Long, ByVal hotkey As Long) As Boolean Private Declare Function CallBase Lib "wulin.dll" (ByVal hWnd As Long, ByVal action As Long) As Boolean CallHotKey(窗体句柄,HotKey) HotKey ====0---------17 分别是0-----9 F1-----F8 CallBase(窗体句柄,Action) Action==0-------N 分别实现不同的功能 Action=0 选怪 函数反回值是 布尔值 ( 窗体句柄,Action 窗体句柄,HotKey 都为DWORD值)
标签： ByVal CallHotKey Function Private
上传时间： 2013-11-25
上传用户：maizezhen
1 #define GPBCON (*(volatile unsigned long *)0x56000010) 2 #define GPBDAT (*(volatile unsigned long *)0x56000014) 3 #define GPFCON (*(volatile unsigned long *)0x56000050) 4 #define GPFDAT (*(volatile unsigned long *)0x56000054)
标签： volatile unsigned define long
上传时间： 2013-12-27
上传用户：BIBI
Traveling Salesman Problem (TSP) has been an interesting problem for a long time in classical optimization techniques which are based on linear and nonlinear programming. TSP can be described as follows: Given a number of cities to visit and their distances from all other cities know, an optimal travel route has to be found so that each city is visited one and only once with the least possible distance traveled. This is a simple problem with handful of cities but becomes complicated as the number increases.
标签： interesting Traveling classical Salesman
上传时间： 2016-02-06
上传用户：rocwangdp
Just what is a regular expression, anyway? Take the tutorial to get the long answer. The short answer is that a regular expression is a compact way of describing complex patterns in texts. You can use them to search for patterns and, once found, to modify the patterns in complex ways. You can also use them to launch programmatic actions that depend on patterns. A tongue-in-cheek comment by programmers is worth thinking about: "Sometimes you have a programming problem and it seems like the best solution is to use regular expressions now you have two problems." Regular expressions are amazingly powerful and deeply expressive. That is the very reason writing them is just as error-prone as writing any other complex programming code. It is always better to solve a genuinely simple problem in a simple way when you go beyond simple, think about regular expressions. Tutorial: Using regular expressions
标签： expression the tutorial regular
上传时间： 2013-12-19
上传用户：sardinescn
编程题（15_01.c） 结构 struct student { long num char name[20] int score struct student *next } 链表练习： (1).编写函数struct student * creat(int n),创建一个按学号升序排列的新链表,每个链表中的结点中 的学号、成绩由键盘输入，一共n个节点。 (2).编写函数void print(struct student *head),输出链表，格式每行一个结点，包括学号，姓名,分数。 (3).编写函数struct student * merge(struct student *a,struct student *b), 将已知的a,b两个链表 按学号升序合并，若学号相同则保留成绩高的结点。 (4).编写函数struct student * del(struct student *a,struct student *b),从a链表中删除b链表中有 相同学号的那些结点。 (5).编写main函数，调用函数creat建立2个链表a,b,用print输出俩个链表；调用函数merge升序合并2个 链表，并输出结果；调用函数del实现a-b,并输出结果。 a: 20304,xxxx,75, 20311,yyyy,89 20303,zzzz,62 20307,aaaa,87 20320,bbbb,79 b： 20302,dddd,65 20301,cccc,99 20311,yyyy,87 20323,kkkk,88 20307,aaaa,92 20322,pppp,83
上传时间： 2016-04-13
上传用户：zxc23456789
堆栈的数据结构和操作 ypedef struct{ HGLOBAL hMem //堆栈全局内存句柄 POINT *lpMyStack //指向该句柄的指针 LONG ElementsNum //堆栈的大小 LONG ptr //指向栈顶得指针
标签： ElementsNum lpMyStack HGLOBAL ypedef
上传时间： 2013-11-26
上传用户：15736969615
//按柱面和磁道来读取磁盘数据,要求 Public Function ReadDisk(ByVal Cylinders As Long, ByVal Tracks As Long, db() As Byte) As Boolean
标签： ByVal Long Cylinders Function
上传时间： 2014-01-13
上传用户：zxc23456789
用AVR单片机设计的MP3播放器 功能： MP3 Player IDE ATA interface FAT 32 with long file name support USB interface On board power supply (input from 7v to 20v DC) Bootloader firmware upgradeable via USB port Infrared bi-directional interface Remote Control Back light graphic LCD worked with only 2x AA batteries In sleep mode sink less than 1uA (2.5mA in active mode) 5 buttons for easy navigation Long range (more than 20 feets)
标签： MP3 interface support Player
上传时间： 2016-07-02
上传用户：fandeshun
C-package of "Long Short-Term Memory" for Protein classification
标签： classification Short-Term C-package Protein
上传时间： 2014-01-24
上传用户：www240697738
编写具有如下原型的函数：int f(unsigned long x, int n, int& Lxn) 它负责将整数x的第n位（从左边数第n位，n>0）的数值放到引用Lxn之中（将作为结果返回到主调函数的对应实参变量中），并将倒数第n位（从右边数第n位，n>0）的数值作为函数结果返回去。并编制主函数对它进行调用以验证其正确性。 例如，当x=123456789，n=7时，执行语句“Rxn=f(x, n, Lxn) ”将使返回的Lxn为7，并使Rxn变为3；而执行语句“Rxn=f(12345, 6, Lxn) ”将使Lxn与Rxn都变为为0（超出数的“长度”即总位数时返回0）。
上传时间： 2017-01-02
上传用户：s363994250
