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elements

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    标签: essential textbooks the European

    上传时间: 2013-12-18

    上传用户:498732662

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    标签: essential textbooks the European

    上传时间: 2014-01-07

    上传用户:qilin

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    标签: essential textbooks the European

    上传时间: 2013-12-17

    上传用户:zl5712176

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    标签: essential textbooks the European

    上传时间: 2013-12-09

    上传用户:stella2015

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    标签: essential textbooks the European

    上传时间: 2014-11-21

    上传用户:cursor

  • 24小时学通Qt编程

    Qt学习资料,界面设计必备。一个跨平台的C++应用程序开发框架。广泛用于开发GUI程序,这种情况下又被称为部件工具箱。也可用于开发非GUI程序,比如控制台工具和服务器。Qt使用于OPIE、Skype、VLC media player、Adobe Photoshop elements、VirtualBox与Mathematica以及被Autodesk 、欧洲空间局、梦工厂、Google、HP、KDE、卢卡斯影业、西门子公司、富豪集团, 华特迪士尼动画制作公司、三星集团、飞利浦、Panasonic 所使用。

    标签: Qt

    上传时间: 2015-12-06

    上传用户:filling87

  • 《Qt及Qt Quick开发实战精解》代码

    《Qt及Qt Quick开发实战精解》代码。Qt(官方发音同cute 发音为/kju:t/,虽然也俗称为Q.T.发音为/kju:tiː/")是一个跨平台的C++应用程序开发框架。广泛用于开发GUI程序,这种情况下又被称为部件工具箱。也可用于开发非GUI程序,比如控制台工具和服务器。Qt使用于OPIE、Skype、VLC media player、Adobe Photoshop elements、VirtualBox与Mathematica以及被Autodesk 、欧洲空间局、梦工厂、Google、HP、KDE、卢卡斯影业、西门子公司、富豪集团, 华特迪士尼动画制作公司、三星集团、飞利浦、Panasonic 所使用。

    标签: 《Qt及Qt Quick开发实战精解》代码

    上传时间: 2015-12-06

    上传用户:filling87

  • 计算本征值程序

    Computes all eigenvalues and eigenvectors of a real symmetric matrix a, ! which is of size n by n, stored in a physical np by np array. ! On output, elements of a above the diagonal are destroyed. ! d returns the eigenvalues of a in its first n elements. ! v is a matrix with the same logical and physical dimensions as a, ! whose columns contain, on output, the normalized eigenvectors of a. ! nrot returns the number of Jacobi rotations that were required. ! Please notice that the eigenvalues are not ordered on output. ! If the sorting is desired, the addintioal routine "eigsrt" ! can be invoked to reorder the output of jacobi.

    标签: 计算 程序

    上传时间: 2016-06-04

    上传用户:1512313

  • C语言算法排序问题

    1.Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two elements in S whose sum is exactly x. (Implement exercise 2.3-7.)

    标签: 算法 排序

    上传时间: 2017-04-01

    上传用户:糖儿水嘻嘻

  • c语言算法排序

    1.Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two elements in S whose sum is exactly x. (Implement exercise 2.3-7.) #include<stdio.h> #include<stdlib.h> void merge(int arr[],int low,int mid,int high){      int i,k;      int *tmp=(int*)malloc((high-low+1)*sizeof(int));      int left_low=low;      int left_high=mid;      int right_low=mid+1;      int right_high=high;      for(k=0;left_low<=left_high&&right_low<=right_high;k++)      {      if(arr[left_low]<=arr[right_low]){                                        tmp[k]=arr[left_low++];                                        }      else{           tmp[k]=arr[right_low++];           } }             if(left_low<=left_high){                              for(i=left_low;i<=left_high;i++){                                                               tmp[k++]=arr[i];                                                               }                              }       if(right_low<=right_high){                              for(i=right_low;i<=right_high;i++)                                                                tmp[k++]=arr[i];                                                        }                              for(i=0;i<high-low+1;i++)                                                       arr[low+i]=tmp[i];       } void merge_sort(int a[],int p,int r){      int q;      if(p<r){              q=(p+r)/2;              merge_sort(a,p,q);              merge_sort(a,q+1,r);              merge(a,p,q,r);              }      } int main(){     int a[8]={3,5,8,6,4,1,1};     int i,j;     int x=10;     merge_sort(a,0,6);     printf("after Merging-Sort:\n");     for(i=0;i<7;i++){                      printf("%d",a[i]);                      }     printf("\n");     i=0;j=6;     do{                                    if(a[i]+a[j]==x){                                  printf("exist");                                  break;                                  }                  if(a[i]+a[j]>x)                                 j--;                  if(a[i]+a[j]<x)                                 i++;                       }while(i<=j);     if(i>j)              printf("not exist");     system("pause");     return 0;     }

    标签: c语言 算法 排序

    上传时间: 2017-04-01

    上传用户:糖儿水嘻嘻