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RANGE-doppler

  • msp430

    msp430The LDC1312 and LDC1314 are 2- and 4-channel, 1• Easy-to-use – minimal configuration required 12-bit inductance to digital converters (LDCs) for • Measure up to 4 sensors with one IC inductive sensing solutions. With multiple channels • Multiple channels support environmental and and support for remote sensing, the LDC1312 and aging compensation LDC1314 enable the performance and reliability benefits of inductive sensing to be realized at minimal• Multi-channel remote sensing provides lowest cost and power. The products are easy to use, onlysystem cost requiring that the sensor frequency be within 1 kHz • Pin-compatible medium and high-resolution and 10 MHz to begin sensing. The wide 1 kHz to 10 options MHz sensor frequency range also enables use of very small PCB coils, further reducing sensing– LDC1312/4: 2/4-ch 12-bit LDC solution cost and size.– LDC1612/4: 2/4-ch 28

    标签: msp 430

    上传时间: 2016-07-22

    上传用户:tongmoonsky

  • 运动会源代码

    #include <malloc.h>       #include <stdio.h>       #include <stdlib.h>       #include <string.h>       #define NULL 0      #define MaxSize 30          typedef struct athletestruct /*运动员*/     {         char name[20];          int score; /*分数*/         int range; /**/         int item; /*项目*/     }ATH;     typedef struct schoolstruct /*学校*/     {         int count; /*编号*/         int serial; /**/          int menscore; /*男选手分数*/         int womenscore; /*女选手分数*/         int totalscore; /*总分*/         ATH athlete[MaxSize]; /**/         struct schoolstruct *next;      }SCH;         int nsc,msp,wsp;      int ntsp;      int i,j;      int overgame;      int serial,range;      int n;      SCH *head,*pfirst,*psecond;      int *phead=NULL,*pafirst=NULL,*pasecond=NULL;     void create();         void input ()     {         char answer;          head = (SCH *)malloc(sizeof(SCH)); /**/         head->next = NULL;         pfirst = head;          answer = 'y';         while ( answer == 'y' )         {         Is_Game_DoMain:         printf("\nGET Top 5 when odd\nGET Top 3 when even");         printf("\n输入运动项目序号 (x<=%d):",ntsp);         scanf("%d",pafirst);         overgame = *pafirst;         if ( pafirst != phead )         {             for ( pasecond = phead ; pasecond < pafirst ; pasecond ++ )             {                 if ( overgame == *pasecond )                 {                     printf("\n这个项目已经存在请选择其他的数字\n");                     goto Is_Game_DoMain;                 }             }         }         pafirst = pafirst + 1;         if ( overgame > ntsp )         {             printf("\n项目不存在");             printf("\n请重新输入");             goto Is_Game_DoMain;         }         switch ( overgame%2 )         {         case 0: n = 3;break;         case 1: n = 5;break;         }         for ( i = 1 ; i <= n ; i++ )         {         Is_Serial_DoMain:         printf("\n输入序号 of the NO.%d (0<x<=%d): ",i,nsc);                 scanf("%d",&serial);         if ( serial > nsc )          {             printf("\n超过学校数目,请重新输入");             goto Is_Serial_DoMain;         }         if ( head->next == NULL )          {             create();         }         psecond = head->next ;          while ( psecond != NULL )          {             if ( psecond->serial == serial )             {                 pfirst = psecond;                 pfirst->count = pfirst->count + 1;                 goto Store_Data;             }             else             {                 psecond = psecond->next;             }         }         create();         Store_Data:                 pfirst->athlete[pfirst->count].item = overgame;         pfirst->athlete[pfirst->count].range = i;         pfirst->serial = serial;         printf("Input name:) : ");                 scanf("%s",pfirst->athlete[pfirst->count].name);         }         printf("\n继续输入运动项目(y&n)?");         answer = getchar();         printf("\n");         }     }         void calculate() /**/     {         pfirst = head->next;         while ( pfirst->next != NULL )         {             for (i=1;i<=pfirst->count;i++)             {                 if ( pfirst->athlete[i].item % 2 == 0 )                  {                     switch (pfirst->athlete[i].range)                     {                     case 1:pfirst->athlete[i].score = 5;break;                     case 2:pfirst->athlete[i].score = 3;break;                     case 3:pfirst->athlete[i].score = 2;break;                     }                 }                 else                  {                     switch (pfirst->athlete[i].range)                     {                     case 1:pfirst->athlete[i].score = 7;break;                     case 2:pfirst->athlete[i].score = 5;break;                     case 3:pfirst->athlete[i].score = 3;break;                     case 4:pfirst->athlete[i].score = 2;break;                     case 5:pfirst->athlete[i].score = 1;break;                     }                 }                 if ( pfirst->athlete[i].item <=msp )                  {                     pfirst->menscore = pfirst->menscore + pfirst->athlete[i].score;                 }                 else                  {                     pfirst->womenscore = pfirst->womenscore + pfirst->athlete[i].score;                 }             }             pfirst->totalscore = pfirst->menscore + pfirst->womenscore;             pfirst = pfirst->next;         }     }         void output()     {         pfirst = head->next;         psecond = head->next;         while ( pfirst->next != NULL )          {             // clrscr();              printf("\n第%d号学校的结果成绩:",pfirst->serial);             printf("\n\n项目的数目\t学校的名字\t分数");             for (i=1;i<=ntsp;i++)              {                 for (j=1;j<=pfirst->count;j++)                  {                     if ( pfirst->athlete[j].item == i )                     {                                                                         printf("\n %d\t\t\t\t\t\t%s\n %d",i,pfirst->athlete[j].name,pfirst->athlete[j].score);break;                                             }                 }             }             printf("\n\n\n\t\t\t\t\t\t按任意建 进入下一页");             getchar();             pfirst = pfirst->next;         }     //  clrscr();          printf("\n运动会结果:\n\n学校编号\t男运动员成绩\t女运动员成绩\t总分");         pfirst = head->next;         while ( pfirst->next != NULL )         {             printf("\n %d\t\t %d\t\t %d\t\t %d",pfirst->serial,pfirst->menscore,pfirst->womenscore,pfirst->totalscore);             pfirst = pfirst->next;         }         printf("\n\n\n\t\t\t\t\t\t\t按任意建结束");         getchar();     }         void create()     {                 pfirst = (struct schoolstruct *)malloc(sizeof(struct schoolstruct));         pfirst->next = head->next ;         head->next = pfirst ;                 pfirst->count = 1;         pfirst->menscore = 0;         pfirst->womenscore = 0;         pfirst->totalscore = 0;     }     void Save()     {FILE *fp;     if((fp = fopen("school.dat","wb"))==NULL)     {printf("can't open school.dat\n");     fclose(fp);     return;     }     fwrite(pfirst,sizeof(SCH),10,fp);     fclose(fp);     printf("文件已经成功保存\n");     }         void main()     {         system("cls");         printf("\n\t\t\t 运动会分数统计\n");         printf("输入学校数目 (x>= 5):");         scanf("%d",&nsc);          printf("输入男选手的项目(x<=20):");         scanf("%d",&msp);          printf("输入女选手项目(<=20):");         scanf("%d",&wsp);          ntsp = msp + wsp;                  phead = (int *)calloc(ntsp,sizeof(int));         pafirst = phead;         pasecond = phead;         input();         calculate();          output();         Save();     }             

    标签: 源代码

    上传时间: 2016-12-28

    上传用户:150501

  • L9352B

    Description The L9352B is an integrated quad low-side power switch to drive inductive loads like valves used in ABS systems. Two of the four channels are current regulators with current range from 0 mA to 2.25 A. All channels are protected against fail functions. They are monitored by a status output.

    标签: L9352B

    上传时间: 2019-03-27

    上传用户:guaixiaolong

  • python爬虫获取大量免费有效代理ip--有效防止ip被封

    以后再也不用担心写爬虫ip被封,不用担心没钱买代理ip的烦恼了 在使用python写爬虫时候,你会遇到所要爬取的网站有反爬取技术比如用同一个IP反复爬取同一个网页,很可能会被封。如何有效的解决这个问题呢?我们可以使用代理ip,来设置代理ip池。 现在教大家一个可获取大量免费有效快速的代理ip方法,我们访问西刺免费代理ip网址 这里面提供了许多代理ip,但是我们尝试过后会发现并不是每一个都是有效的。所以我们现在所要做的就是从里面提供的筛选出有效快速稳定的ip。 以下介绍的免费获取代理ip池的方法: 优点:免费、数量多、有效、速度快 缺点:需要定期筛选 主要思路: 从网址上爬取ip地址并存储 验证ip是否能使用-(随机访问网址判断响应码) 格式化ip地址 代码如下: 1.导入包 import requests from lxml import etree import time 1 2 3 2.获取西刺免费代理ip网址上的代理ip def get_all_proxy():     url = 'http://www.xicidaili.com/nn/1'     headers = {         'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/68.0.3440.106 Safari/537.36',     }     response = requests.get(url, headers=headers)     html_ele = etree.HTML(response.text)     ip_eles = html_ele.xpath('//table[@id="ip_list"]/tr/td[2]/text()')     port_ele = html_ele.xpath('//table[@id="ip_list"]/tr/td[3]/text()')     proxy_list = []     for i in range(0,len(ip_eles)):         proxy_str = 'http://' + ip_eles[i] + ':' + port_ele[i]         proxy_list.append(proxy_str)     return proxy_list 1 2 3 4 5 6 7 8 9 10 11 12 13 14 3.验证获取的ip def check_all_proxy(proxy_list):     valid_proxy_list = []     for proxy in proxy_list:         url = 'http://www.baidu.com/'         proxy_dict = {             'http': proxy         }         try:             start_time = time.time()             response = requests.get(url, proxies=proxy_dict, timeout=5)             if response.status_code == 200:                 end_time = time.time()                 print('代理可用:' + proxy)                 print('耗时:' + str(end_time - start_time))                 valid_proxy_list.append(proxy)             else:                 print('代理超时')         except:             print('代理不可用--------------->'+proxy)     return valid_proxy_list 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 4.输出获取ip池 if __name__ == '__main__':     proxy_list = get_all_proxy()     valid_proxy_list = check_all_proxy(proxy_list)     print('--'*30)     print(valid_proxy_list) 1 2 3 4 5 技术能力有限欢迎提出意见,保证积极向上不断学习 ———————————————— 版权声明:本文为CSDN博主「彬小二」的原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接及本声明。 原文链接:https://blog.csdn.net/qq_39884947/article/details/86609930

    标签: python ip 代理 防止

    上传时间: 2019-11-15

    上传用户:fygwz1982

  • AD810

    PRODUCT DESCRIPTION The AD810 is a composite and HDTV compatible, current feedback, video operational amplifier, ideal for use in systems such as multimedia, digital tape recorders and video cameras. The 0.1 dB flatness specification at bandwidth of 30 MHz (G = +2) and the differential gain and phase of 0.02% and 0.04° (NTSC) make the AD810 ideal for any broadcast quality video system. All these specifications are under load conditions of 150 Ω (one 75 Ω back terminated cable). The AD810 is ideal for power sensitive applications such as video cameras, offering a low power supply current of 8.0 mA max. The disable feature reduces the power supply current to only 2.1 mA, while the amplifier is not in use, to conserve power. Furthermore the AD810 is specified over a power supply range of ±5 V to ±15 V.

    标签: 810 AD

    上传时间: 2020-04-19

    上传用户:su1254

  • AD8001AR

    transimpedance linearization circuitry. This allows it to drive video loads with excellent differential gain and phase perfor mance on only 50 mW of power. The AD8001 is a current feedback amplifier and features gain flatness of 0.1 dB to 100 MHz while offering differential gain and phase error of 0.01% and 0.025°. This makes the AD8001 ideal for professional video electronics such as cameras and video switchers. Additionally, the AD8001’s low distortion and fast settling make it ideal for buffer high-speed A-to-D converters. The AD8001 offers low power of 5.5 mA max (VS = ±5 V) and can run on a single +12 V power supply, while being capable of delivering over 70 mA of load current. These features make this amplifier ideal for portable and battery-powered applications where size and power are critical. The outstanding bandwidth of 800 MHz along with 1200 V/µs of slew rate make the AD8001 useful in many general purpose high-speed applications where dual power supplies of up to ±6 V and single supplies from 6 V to 12 V are needed. The AD8001 is available in the industrial temperature range of –40°C to +85°C.

    标签: 8001 AD AR

    上传时间: 2020-04-21

    上传用户:su1254

  • 3GPP LTE Radio and Cellular Technology

    This book provides technical information about all aspects of 3GPP LTE. The areas covered range from basic concepts to research-grade material, including future directions. The book captures the current state of 3GPP LTE technology and serves as a source of comprehensive reference material on this subject. It has a total of 12 chapters authored by 50 experts from around the world. The targeted audi- ence includes professionals who are designers or planners for 3GPP LTE systems, researchers (faculty members and graduate students), and those who would like to learn about this field.

    标签: Technology Cellular Radio 3GPP LTE and

    上传时间: 2020-05-26

    上传用户:shancjb

  • Ambient Networks

    One traditional view of how wireless networks evolve is of a continuous, inevitable progres- sion to higher link speeds, combined with greater mobility over wider areas. This standpoint certainly captures the development from first and second generation cellular systems focused on voice support, and the early short-range wireless data networks, through to today’s 3G cellular and mobile broadband systems; there is every confidence that the trend will continue some way into the future. 

    标签: Networks Ambient

    上传时间: 2020-05-26

    上传用户:shancjb

  • Cognitive+Radio+Networks

    According to the statistics of the Federal Communications Commission (FCC), temporal and geographical variations in the utilization of the as- signed spectrum range from 15% to 85%. The limited available radio spec- trum and the inefficiency in spectrum usage necessitate a new commu- nication paradigm to exploit the existing spectrum dynamically. 

    标签: Cognitive Radio Networks

    上传时间: 2020-05-26

    上传用户:shancjb

  • Cognitive+Radio+Technology

    This introduction takes a visionary look at ideal cognitive radios (CRs) that inte- grate advanced software-defined radios (SDR) with CR techniques to arrive at radios that learn to help their user using computer vision, high-performance speech understanding, global positioning system (GPS) navigation, sophisticated adaptive networking, adaptive physical layer radio waveforms, and a wide range of machine learning processes.

    标签: Technology Cognitive Radio

    上传时间: 2020-05-26

    上传用户:shancjb