此代码是EASYARM调试程序的Flash的c＋＋代码，硬件调试ok，并且本人画的PCB板上也调试ok
上传时间： 2014-01-05
上传用户：evil
PrintNow is a 32-bit application that runs only under Windows 95 or Windows NT 4.0. It allows your PrtScr and Alt+PrtScr keys to print a screen capture directly to your printer instead of just copying the image to the Windows clipboard. PrintNow can also print any DIB image in the clipboard, regardless of its original source. PrintNow supports multiple instances, it can print multiple copies of a screen capture to the same printer with different print settings, to several different printers, or any combination thereof, with a single keystroke.
标签： Windows application PrintNow allows
上传时间： 2015-04-27
上传用户：zhanditian
接收pop3 Public Function Retrieve(ByVal rhs As Pop3Message) As Pop3Message Dim message, response As String Dim msg As New Pop3Message msg.bytes = rhs.bytes msg.number = rhs.number message = "RETR " + rhs.number.ToString + vbCrLf write(message) response = Respond() If response.Substring(0, 3) <> "+OK" Then Throw New Pop3Exception(response) End If MsgBox(msg) msg.retrieved = True While (1 = 1) response = Respond() If response = "." + vbCrLf Then Exit While Else msg.message += response End If End While Return msg End Function
标签： Pop3Message Function Retrieve response
上传时间： 2013-12-28
上传用户：fnhhs
to show the waveform of audio file and play it on computer Purpose: Familiar with WAV file format and UI design It should have the following functions: Provide a Graphic User Interface for user to browse the file system and select one WAV file Show the waveform of input audio signal Play the selected WAV file Print the parameters of WAV file such as sampling rate, bit-depth, etc
标签： file Familiar computer waveform
上传时间： 2015-05-07
上传用户：l254587896
ARM下 Implement matrix multiplication of 2 square matrices, with data read from an input file and printed both to the console and to an output file. • Assume a file with correct data (no garbage, characters, etc.). • you must check and provide appropriate execution for 2 extra cases, namely when the matrix size given is either “0” , or when the size is greater than the maximum handled of “5” . In these 2 cases you must implement the following behaviour: o If size = 0, then print a message “Size = 0 is unacceptable” and continue by reading the next size for the next 2 matrices (if not end of file). o If size >5, then print two messages: “Size is too big - unacceptable”. Then read and discard the next (size2 ) integers and continue by reading the next size for the next 2 matrices (if not end of file).
标签： multiplication Implement matrices matrix
上传时间： 2014-08-30
上传用户：dsgkjgkjg
数字运算，判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no
上传时间： 2015-05-21
上传用户：daguda
这是我的课程设计 由于时间有限，程序难免有不足。 还请多多指教。 程序建议不要在win2000和win xp的cmd下运行。 推荐在win98或纯dos中装有UCDOS中文DOS平台下运行。 主菜单程序为main.c 运行此程序，选择相应的菜单，即可运行查看到其他程序。 wnl.c万年历 adstd.c 学生数据库 ply.c小蜜蜂（UFO）游戏 tlife 生存模拟 但是要求main.c和其他程序的执行文件必须在同一目录里（文件夹）。否则连接其他程序将失败。 建议直接运行我已经编译好的执行文件(在ok目录下)运行main.exe即可通过菜单对四个程序进行调用。 如果发现不能正常使用本程序，请与我联系。 寝室电话:0732-8370551 7324474 QQ176141729 email:coynnbai@163.com 学生：陈欢 班级：03级计算机6班
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上传时间： 2014-01-27
上传用户：wuyuying
linux操作系统下运行，print current directory s files
上传时间： 2014-01-13
上传用户：shawvi
AVR浮点运算，算法比较OK，对开发AVR单片机比较有用。
上传时间： 2013-11-25
上传用户：阿四AIR
2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1. Input One positive integer on each line, the value of n. Output If the minimum x exists, print a line with 2^x mod n = 1. Print 2^? mod n = 1 otherwise. You should replace x and n with specific numbers. Sample Input 2 5 Sample Output 2^? mod 2 = 1 2^4 mod 5 = 1
标签： mod satisfies minimum number
上传时间： 2015-06-02
上传用户：qlpqlq
