// Copyright (c), Philips Semiconductors Gratkorn // (C)PHILIPS Electronics N.V.2000 // ALL rights are reserved. // Philips reserves the right to make changes without notice at any time. // Philips makes no warranty, expressed, implied or statutory, including but // not limited to any implied warranty of merchantibility or fitness for any //particular purpose, or that the use will not infringe any third party patent, // copyright or trademark. Philips must not be liable for any loss or damage // arising from its use.
标签： Semiconductors Electronics Copyright Gratkorn
上传时间： 2016-02-04
上传用户：xuanjie
broad cast could send the message to ALL the user from the im server, which is one module of the openfire,
上传时间： 2014-01-21
上传用户：英雄
一个关于DOS使用的文档,很全面,对于新手很是有用.-DOS use common sense on a very comprehensive documentation, I believe ALL of us are also used.
标签： comprehensive documentation DOS believe
上传时间： 2014-08-09
上传用户：duoshen1989
2． Using QR factorization to find ALL of the eigenvalues and eigenvectors for the following matrix
标签： factorization eigenvectors eigenvalues following
上传时间： 2014-01-14
上传用户：cuiyashuo
his header file that is used to define ALL preprossor directives, global variables, and prototypes. The user must modify this header file for their particular Bridge Transducer in use before proceeding.
标签： directives preprossor prototype variables
上传时间： 2014-08-24
上传用户：李彦东
8路红外遥控开关控制器 (SAA3010T电视遥控器) Copyright 2004/3/27 http://www.cdle.net http://bbs.cdle.net ALL rights reserved. 明浩 E-mail: pnzwzw@163.com pnzwzw@cdle.net 只用八路时可以用AT89C2051代替AT89C51 一体化接收头输出端拉P3.2(int0)，P1为控制输出端。 可以扩展到32路或更多 输出为低电平有效
上传时间： 2016-02-11
上传用户：qunquan
Philips D12 ALL the data
上传时间： 2013-12-22
上传用户：Pzj
Floyd-WarshALL算法描述 1)适用范围： a)APSP(ALL Pairs Shortest Paths) b)稠密图效果最佳 c)边权可正可负 2)算法描述： a)初始化：dis[u,v]=w[u,v] b)For k:=1 to n For i:=1 to n For j:=1 to n If dis[i,j]>dis[i,k]+dis[k,j] Then Dis[I,j]:=dis[I,k]+dis[k,j] c)算法结束：dis即为所有点对的最短路径矩阵 3)算法小结：此算法简单有效，由于三重循环结构紧凑，对于稠密图，效率要高于执行|V|次Dijkstra算法。时间复杂度O(n^3)。 考虑下列变形：如(I,j)∈E则dis[I,j]初始为1,else初始为0，这样的Floyd算法最后的最短路径矩阵即成为一个判断I,j是否有通路的矩阵。更简单的，我们可以把dis设成boolean类型，则每次可以用“dis[I,j]:=dis[I,j]or(dis[I,k]and dis[k,j])”来代替算法描述中的蓝色部分，可以更直观地得到I,j的连通情况。
标签： Floyd-WarshALL Shortest Pairs Paths
上传时间： 2013-12-01
上传用户：dyctj
Speed-Up Delphi for ALL version
标签： Speed-Up version Delphi for
上传时间： 2016-02-21
上传用户：lo25643
we ALL can use it by yourself
上传时间： 2016-02-26
上传用户：从此走出阴霾
