ICTCLAS的JNI调用接口文件: Title:ICTCLAS Caller * <p>Description:do chinese word segmentation.don t change the pakage and CLASS name, orelse you can t use it. * 请不要改变包名、类名以及native的方法名，否则调用将失效。 * 由于ICTCLAS本身存在很多鲁棒性问题，调用segSentence时，string参数请保证不要过长或带有乱码。调用次数过多（如处理几十G的数据）会有可能造成内存溢出。 * 故基本只能用于较小规模数据（相对几十G来说）。 * 请运行时设置jvm足够的堆栈空间。
标签： ICTCLAS segmentation Description chinese
上传时间： 2014-01-25
上传用户：it男一枚
See Appendix B for a Description of the programs included on this companion disk. RESOURCE.WRI identifies other books and resources for Internet programming. WEBHELP.HLP contains an introduction to the World Wide Web. TCPMAN.HLP provides detailed instructions to help you use the Trumpet Winsock included on this disk. Use the Program Manager s File menu Run option to execute the SETUP.EXE program found on this disk. SETUP.EXE will install the programs on your hard drive and create an Internet Programming group window. Internet编程技术 [配套程序] [涉及平台] VC [作者] void [文件大小] 1032K
标签： Description companion Appendix RESOURCE
上传时间： 2013-12-04
上传用户：asasasas
This Verilog HDL Description implements a UART.
标签： Description implements Verilog This
上传时间： 2013-12-17
上传用户：wff
Details Description of Free BSD network source code.Those documents have explained each line of code.
标签： code Description documents explained
上传时间： 2015-07-01
上传用户：fandeshun
CML2 Language and Tools Description(EN).rar
标签： Description Language Tools CML2
上传时间： 2015-08-06
上传用户：netwolf
PCB Language and Tools Description(EN).rar
标签： Description Language Tools PCB
上传时间： 2013-12-23
上传用户：气温达上千万的
CML2 Language and Tools Description(EN).rar
标签： Description Language Tools CML2
上传时间： 2013-11-30
上传用户：gyq
Name:neural Network Control, for Matlab,tipical Description for control problems with NN method, additionally, there are some useful examples to be referenced.
标签： Description for problems Control
上传时间： 2015-08-15
上传用户：siguazgb
ACM试题An Easy Problem Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
标签： Description computers Problem binary
上传时间： 2013-12-11
上传用户：libenshu01
ACM试题Problem K:Ones Description Given any integer 0 <= n <= 10000 not divisible by 2 or 5, some multiple of n is a number which in decimal notation is a sequence of 1 s. How many digits are in the smallest such a multiple of n?
标签： Description divisible Problem integer
上传时间： 2015-08-23
上传用户：zhenyushaw
